Subnetting Quiz 1

Test your IPv4 Subnetting knowledge with  Subnetting Quiz 1! Practice with 20 Subnetting Questions and answer  explanations covering subnet masks, IP address classes, binary conversions, network and broadcast addresses, usable host ranges and basic subnetting calculations. Solve Subnetting Practice Questions below and improve your subnetting skills for the CCNA exam and real-world networking.

Subnetting Questions – Quiz 1

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Question 1
A network engineer is given the IP address 102.74.200.1/23. Which of the following addresses belongs to the same subnet and can be assigned to a host?
A
102.74.202.1
B
102.74.199.254
C
102.74.201.200
D
102.74.200.0
E
102.74.201.255
Question 1 Explanation: 
The IP address 102.74.200.1/23 belongs to the network 102.74.200.0/23, with subnet mask 255.255.254.0. - Network Address: 102.74.200.0 - First Usable Host: 102.74.200.1 - Last Usable Host: 102.74.201.254 - Broadcast Address: 102.74.201.255
Question 2
Which IPv4 prefix length allows both addresses to be used on a modern point-to-point router link without separate network and broadcast addresses?
A
/29
B
/27
C
/30
D
/31
E
/28
Question 2 Explanation: 
RFC 3021 allows both IPv4 addresses in a /31 prefix to be used on a point-to-point link, reducing address consumption compared with a traditional /30 subnet.
Question 3
What is the broadcast address of the IPv4 network 172.18.16.0/21?  
A
172.18.25.255
B
172.18.255.255
C
172.18.30.255
D
172.18.23.255
E
172.18.0.255
Question 3 Explanation: 
A /21 subnet uses the mask 255.255.248.0, creating blocks of 8 in the third octet. The network spans 172.18.16.0 through 172.18.23.255.
Question 4
Which of the following IPv4 addresses belongs to Class A in classful addressing?
A
10.1.152.8
B
192.1.52.5
C
172.8.10.1
D
172.8.202.140
E
200.55.12.34
Question 5
What is the decimal equivalent of the 8-bit binary number 01001010?
A
74
B
72
C
142
D
140
E
70
Question 6
A network engineer needs a subnet that supports at least 50 usable IPv4 host addresses. Which subnet mask provides the smallest suitable subnet?
A
255.255.255.240
B
255.255.255.192
C
255.255.255.0
D
255.255.255.128
E
255.255.255.224
Question 6 Explanation: 
A /26 subnet provides 64 total addresses and 62 usable host addresses. A /27 supports only 30 usable hosts, so /26 is the smallest suitable subnet.
Question 7
A company divides the network 80.160.0.0/16 into equal-sized /20 subnets. How many subnets are created, and how many usable host addresses are available in each subnet?
A
16 subnets, 4,094 usable hosts
B
32 subnets, 4,094 usable hosts
C
32 subnets, 2,046 usable hosts
D
8 subnets, 8,190 usable hosts
E
16 subnets, 2,046 usable hosts
Question 7 Explanation: 
Moving from /16 to /20 borrows 4 bits, creating 2⁴ = 16 subnets. A /20 subnet leaves 12 host bits, providing 2¹² − 2 = 4,094 usable host addresses per subnet.
Question 8
What is the 8-bit binary equivalent of the decimal number 188?
A
10001111
B
10111101
C
10110000
D
10101100
E
10111100
Question 9
A company has the network 192.168.1.0/24 and needs at least 7 equal-sized subnets. Each subnet must support at least 18 usable host addresses. Which subnet mask meets both requirements?
A
255.255.255.128
B
255.255.255.240
C
255.255.255.248
D
255.255.255.224
E
255.255.255.192
Question 9 Explanation: 
A /27 mask divides a /24 network into 8 equal-sized subnets, each supporting 30 usable host addresses. This meets both requirements.
Question 10
What is the network address of the IPv4 host 100.155.1.0/21?
A
100.155.255.1/21
B
100.155.0.0/21
C
100.155.255.0/21
D
100.155.1.0/21
E
100.155.0.255/21
Question 10 Explanation: 
A /21 subnet has a block size of 8 in the third octet. The address 100.155.1.0 belongs to the network 100.155.0.0/21.
Question 11
What is the dotted-decimal subnet mask for an IPv4 /26 prefix?
A
255.255.255.240
B
255.255.255.192
C
255.255.255.248
D
255.255.255.0
E
255.255.255.224
Question 11 Explanation: 
A /26 prefix contains 26 network bits. Its subnet mask is 255.255.255.192, leaving 6 bits for host addresses.
Question 12
Which IPv4 address class does 172.16.1.1 belong to in classful addressing?
A
Class A
B
Class D
C
Class B
D
Class C
E
Class E
Question 13
A network engineer needs to divide 192.168.1.0/24 into at least 5 equal-sized subnets. Which subnet mask provides the maximum number of usable hosts per subnet while meeting this requirement?
A
255.255.255.248
B
255.255.255.224
C
255.255.255.254
D
255.255.255.252
E
255.255.255.240
Question 13 Explanation: 
Borrowing 3 bits from a /24 creates 8 subnets. A /27 mask provides 30 usable host addresses per subnet.
Question 14
How many usable IPv4 host addresses are available in a standard subnet with mask 255.255.255.0?
A
1
B
255
C
2
D
224
E
254
Question 14 Explanation: 
A /24 subnet has 8 host bits, providing 256 total addresses. Excluding the network and broadcast addresses leaves 254 usable host addresses.
Question 15
What is the last usable host address in the network 182.144.10.0/29?
A
182.144.10.0
B
182.144.10.1
C
182.144.10.255
D
182.144.10.6
E
182.144.10.254
Question 15 Explanation: 
A /29 subnet contains 8 addresses. The network address is 182.144.10.0, the broadcast address is 182.144.10.7, and the usable range is 182.144.10.1–182.144.10.6.
Question 16
Which of the following is the correct binary representation of the IPv4 address 201.18.171.15?
A
11001001.00010010.10101011.00011111
B
11001000.00010010.10101011.00001111
C
11001001.00010011.10101011.00001111
D
11001001.00010010.10101011.00001111
E
11001001.00010010.10101010.00001111
Question 17
Which IPv4 subnet contains the host address 12.120.1.185/25?
A
12.120.1.128/25
B
12.120.1.64/25
C
12.120.1.1/25
D
12.120.1.192/25
E
12.120.1.0/25
Question 17 Explanation: 
A /25 subnet has a block size of 128 in the fourth octet. The address 12.120.1.185 falls within 12.120.1.128–12.120.1.255, so its network address is 12.120.1.128.
Question 18
What is the correct binary representation of the subnet mask 255.255.128.0?
A
11111111.11111111.00000001.00000000
B
11111111.11111111.11111111.00000001
C
11111111.11111111.11111111.00000000
D
11111111.11111111.00000000.00000000
E
11111111.11111111.10000000.00000000
Question 19
What is the first usable host address in the network 172.18.16.0/21?
A
172.18.16.0
B
172.18.16.15
C
172.18.16.1
D
172.18.16.54
E
172.18.16.16
Question 19 Explanation: 
The network address is 172.18.16.0. The first usable host address is the next address, 172.18.16.1.
Question 20
Which usable host range contains the IPv4 address 10.145.100.6/27?
A
10.145.100.1 - 10.145.100.30
B
10.145.100.0 - 10.145.100.255
C
10.145.100.1 - 10.145.100.255
D
10.145.100.0 - 10.145.100.63
E
10.145.100.0 - 10.145.100.32
Question 20 Explanation: 
The address belongs to 10.145.100.0/27. This subnet has a broadcast address of 10.145.100.31 and a usable host range of 10.145.100.1–10.145.100.30.
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